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If your compiler only has one pass at the nodes in your abstract syntax tree, and you have an if/else statement, how can it know ahead of time where you want it to jump to in the else case?
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If your compiler only has one pass at the nodes in your abstract syntax tree, and you have an if/else statement, how can it know ahead of time where you want it to jump to in the else case?
0 reposts0 likes