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Higher-order functions take other functions as arguments. The fun part: you must not inline the call unless the target is constant - otherwise you break semantics (and your VM). #kotlin

What exactly is the “order” of a function? Is it a number? Who is number 1? Are you number 6?

What about this Python function, then: def f(g) : return g What order does f(f) return?

I think it's useless to try and evaluate the order of a function where the parameter doesn't have a strict static type, because whatever order of function you have, you can always make it have an order one higher. So basically,

Essentially, functions in Python are just one big "function" type, and because the order of a function depends on its parameters, and parameter types can change in Python, it's impossible to know. For example, what would the order of this function be?

In your example, f is simply a higher-order function. That's it. In a typed programming language it returns a function of the same order as its argument, and the order of the function itself is the order of the argument plus one.

So the order of f is one greater than the order of f?