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Elixir ▷ Max
@mxgrn.com

I don't know who needs to hear this, but this works in #ElixirLang (new line after :foo is key): if true, do: (:foo :bar) Can you guess what it returns?

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Hauleth
@hauleth.dev

`:bar` as what you have inside parens is a code block. It is the same as if true do :foo :bar end Just written in a funky way.

Hauleth
@hauleth.dev

In theory that would be equivalent to `__block__(1, 2)`, but that will be rejected by the compiler/interpreter. Elixir is funky sometimes.